Ix(a,b)≈M∑n=0∞pnJn(b,u);a>bM=H(b,u)Γ(a+b)Γ(a)TbH(c,u)=e−uucΓ(a)T=a+b−12u=−Tln(x)p0=1pn=(b−1)(2n−1)!+1n∑m=1n−1(mb−n)(2m+1)!pn−m